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A globe company currently manufactures a globe that is 16 inches in diameter. If the dimensions of the globe were reduced by half, what would its volume be? Use 3.14 for π and round your answer to the nearest tenth.

682.7 in^3
2143.6 in^3
85.3 in^3
267.9 in^3

Answer :

If dimensions of the globe that is 16 inches in diameter were reduced by half, then its volume would be [tex]$V= 267.9 \text{ in}^{3}$[/tex]

What is volume ?

The volume of an object is a measure of the amount of space occupied by that object.

Here given that originally diameter was 16 inches but then dimensions of the globe was reduced by half

The new diameter is equal to

[tex]$D=16 / 2=8 \mathrm{in}$[/tex]

Hence radius is equal to

[tex]$r=8 / 2=4 \mathrm{in}$[/tex]

The volume of the reduced globe is

[tex]$V=\frac{4}{3}(\pi)(r)^{3}$[/tex]

[tex]$V=\frac{4}{3}(3.14)(4)^{3}$\\[/tex]

[tex]$V= 267.9 \text{ in}^{3}$[/tex]

If dimensions of the globe that is 16 inches in diameter were reduced by half, then its volume would be [tex]$V= 267.9 \text{ in}^{3}$[/tex]

To learn more about volume visit : https://brainly.com/question/1972490