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Answer :

Oladayoademosugo

Answer:

6.27 × 10⁻⁴

Explanation:

Relative roughness, k = ε/D where ε = absolute roughness = 0.0025 mm and D = internal pipe diameter = 0.157 in = 0.157 × 25.4 mm = 3.9878 mm

So, k = ε/D

= 0.0025 mm/3.9878 mm

= 6.27 × 10⁻⁴

Cricetusgo

The relative pipe roughness for a plastic pipe will be:

"6.27 × 10⁻⁴".

Relative roughness of pipe

According to the question,

Absolute roughness, ε = 0.0025 mm

Internal pipe diameter, D = 0.157 in or,

                                          = 0.157 × 25.4 mm

                                          = 3.9878 mm

We know that,

The relative roughness be:

→ k = [tex]\frac{Absolute \ roughness}{Diameter}[/tex]

or,

   k = [tex]\frac{\varepsilon }{D}[/tex]

By substituting the above values,

      = [tex]\frac{0.0025}{3.9878}[/tex]

      = 6.27 × 10⁻⁴

Thus the above approach is correct.

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