Answer :
Answer:
max Diameter = 0.530 mm
Explanation:
Calculate the maximum Diameter that the thermocouple should have
applying this formula : e = [tex]\frac{SvCv}{hA}[/tex] ------ ( 1 )
mass = density * volume
Time constant = mc / hA
attached below is the detailed solution
r ( diameter ) = 0.530 mm
