The solutions to the quadratic equation [tex]4(x+2)^2=36[/tex] are x = -5 and x = 1.
Given the following data:
How to solve a quadratic equation.
In this exercise, you're required to determine the value of x by solving for the factors (roots) of the given quadratic equation.
In Mathematics, the standard form of a quadratic equation is given by;
[tex]ax^2 + bx + c =0[/tex]
Where:
Dividing both sides by 4, we have:
[tex]4(x+2)^2=36\\\\(x+2)^2=9[/tex]
Taking the square root of both sides, we have:
[tex]x+2=\pm3\\\\x=\pm 3-2[/tex]
x = -5 or 1.
Read more on quadratic equation here: brainly.com/question/1214333
