1. Write an equation for the circle whose graph is shown.
y
5
3
2
-5 -4 -3 -2 -1
1 2 3 4 5 x
2
3
-4
-5
O (3-1)2 + (y + 2)2 = 2
O (3-1)2 + (x + 2)2 = 4
O (2+1)2 + (y – 2)2 = 4
O (2+1)2 + (y-2)2

The required equation of the circle that shown in the graph is,
(x + 1)² + (y - 2)² = 4 where (-1 , 2) is the center of the circle and 2 unit is the radius of the circle. Option C is correct.

A graph of the circle is shown, It is to determine the equation of the circle.

What is a circle?

The circle is the locus of a point whose distance from a fixed point is constant i.e center (h, k). The equation of the circle is given by

(x - h)² + (y - k)² = r²

where h, k is the coordinate of the circle's center on the coordinate plane and r is the circle's radius.

From the graph, the center is ( -1, 2) and the radius is 2. Now put these values in the standard equation of the circle.
(x - (-1))² + (y - 2)² = 2²
(x +1 )² + (y - 2)² = 4

Thus, the required equation of the circle that shown in the graph is,
(x + 1)² + (y - 2)² = 4 where (-1 , 2) is center of the circle and 2 unit is the radius of the circle. Option C is correct.

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1. Write an equation for the circle whose graph is shown. y 5 3 2 -5 -4 -3 -2 -1 1 2 3 4 5 x 2 3 -4 -5 O (3-1)2 + (y + 2)2 = 2 O (3-1)2 + (x + 2)2 = 4 O (2+1)2 + (y – 2)2 = 4 O (2+1)2 + (y-2)2

Answer :

What is a circle?

Go Teaching: Other Questions

1. Write an equation for the circle whose graph is shown.
y
5
3
2
-5 -4 -3 -2 -1
1 2 3 4 5 x
2
3
-4
-5
O (3-1)2 + (y + 2)2 = 2
O (3-1)2 + (x + 2)2 = 4
O (2+1)2 + (y – 2)2 = 4
O (2+1)2 + (y-2)2