Answer:
33.23 %
Explanation:
First we convert 34 g of O₂ into moles, using its molar mass:
- 34 g O₂ ÷ 32 g/mol = 1.0625 mol O₂
Then we convert O₂ moles into Cs₂O moles, using the stoichiometric coefficients of the balanced reaction:
- 1.0625 mol O₂ * [tex]\frac{2molCs_2O}{1molO_2}[/tex] = 2.125 mol Cs₂O
Now we convert 2.125 moles of Cs₂O into grams, using its molar mass:
- 2.125 mol Cs₂O * 281.81 g/mol = 598.85 g Cs₂O
598.85 g is the theoretical yield. Finally we proceed to calculate the percent yield:
- 199 / 598.85 * 100% = 33.23 %
