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Answer :

Answer:

0.54 L

Explanation:

Given that,

Initial volume, V₁ = 0.5 L

Initial temperature, T₁ = 10°C = 283 K

Final temperature, T₂ = 35 C = 308 K

We need to find the final volume. The relation between the volume and temperature is given by :

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{0.5\times 308 }{283}\\\\V_2=0.54\ L[/tex]

So, the new volume is 0.54 L.

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