Find the area of the garden.

Answer:
28yd²
Step-by-step explanation:
area of square = side *side
=6*6= 36²
area of rectangle (patio)= length* breadth
=4*2=8²
area of garden= area of square - area of rectangle
=36-8
=28 yd²
Answer:
Step-by-step explanation:
First Case:
Given,
Side of the big square = 6 yd
Therefore,
Area of the big square = side × side
= 6yd × 6yd
[tex] = 36 {yd}^{2} [/tex]
Second Case:
Length of the patio = 4 yd
Breadth of the patio = 2 yd
Therefore,
Area of the patio = Length × Breadth
= 4yd × 2yd
[tex] = 8 {yd}^{2} [/tex]
Last Case:
According to first and second cases,
Area of the garden
= Area of the big square - Area of the patio
[tex] = 36 {yd}^{2} - 8 {yd}^{2} [/tex]
[tex] = 28 {yd}^{2} [/tex]
Required area of the garden is 28 sq. yd (Ans)