How many solutions would there be for the following system of equations? y = 3x - 5 67 – 2g = 10 A 1 Solution B 2 Solutions c) No solution D Infinitely Many solutions

Answer:
D
Step-by-step explanation:
Given the 2 equations
y = 3x - 5 → (1)
6x - 2y = 10 → (2)
Substitute y = 3x - 5 into (2)
6x - 2(3x - 5) = 10
6x - 6x + 10 = 10 ( subtract 10 from both sides )
6x - 6x = 0 , that is
0 = 0 ← True
This indicates the system has infinitely many solutions → D