Answer:
Therefore, Cylinder B's surface area is four times greater than Cylinder A's surface area.
Step-by-step explanation:
Surface area of a cylinder = 2πrh+2πr² = 2π(rh+r²)
Cylinder A = 2π(rh+r²)
Cylinder B = 2π((2r)(2h)+(2r)²) = 2π(4rh+4r²)=2π(4(rh+r²))
To find how many times greater Cylinder B's surface area is than Cylinder A's surface area, divide:
[tex]\frac{Cylinder B}{Cylinder A}[/tex]
=2π(4(rh+r²))/2π(rh+r²)
(divide top and bottom by 2Ï€)
=4(rh+r²)/(rh+r²)
(divide top and bottom by (rh+r²))
=4
Therefore, Cylinder B's surface area is four times greater than Cylinder A's surface area.
