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This is my 6th time posting this questions. please not bots or links
and please *explain* the answer and steps
I really need help understanding this.
describe the process to determine the limiting reactant in the example listed below:
Given 3.4 grams of x element with a molar mass of 24 g/mol and 4.2 grams of y element with a molar mass of 35 g/mol. How much of compound xy2 can be generated?
x + 2y -> xy2

Answer :

Osenigo

The amount of the compound [tex]XY_2[/tex] that can be generated would be 11.28 grams

Stoichiometric calculation

From the equation of the reaction, the mole ratio of X and Y is 1:1.

Mole of 3.5 grams of X = 3.4/24 = 0.1417 moles

Mole of 4.2 grams of Y = 4.2/35 = 0.12 moles

Thus, Y is the limiting reactant because it is present in a lower amount than needed.

Mole ratio of Y and  [tex]XY_2[/tex] = 1:1

Equivalent mole of  [tex]XY_2[/tex] = 0.12 moles

Molar mass of  [tex]XY_2[/tex] = 24 + (35x2) = 94 g/mol

Mass of 0.12 moles of  [tex]XY_2[/tex] = 0.12 x 94 = 11.28 grams

More on stoichiometric calculations can be found here: https://brainly.com/question/27287858

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