Answer:
[tex]4x-y=18[/tex]
Step-by-step explanation:
We want to find the equation of a line in standard form with a slope of 4 and passes through the point (6, 6).
First, we can write it in point-slope form. Point-slope form is given by:
[tex]y-y_1=m\left(x-x_1\right)[/tex]
Where (x₁, y₁) is a point and m is the slope.
Substitute:
[tex]y-6=4(x-6)[/tex]
Distribute the right:
[tex]y-6=4x-24[/tex]
Now, we can separate all the variables and the constants. Subtract 4x from both sides:
[tex]-4x+y-6=-24[/tex]
Add add 6 to both sides:
[tex]-4x+y=-18[/tex]
Traditionally, A or the coefficient of x is always positive. Hence, we can divide both sides by -1 to acquire:
[tex]4x-y=18[/tex]
