Please help me with 1,2,3,4,5,6 please

Answer:
all of these are right angled triangle. so u can use pythagoras theorem, h²=p²+b²
longest side is called hypotenious (h)
and u can assume any of the remaining side as p and b as your choice
eg=
1) h=13
p=12
b=?
using pythagrous theroem
h²=p²+b²
13²=12²+b²
169= 144+b²
169-144=b²
25=b²
25 is the square root of 5 so
5²=b²
square root of each side will be cancelled so
b = 5
In this way u can solve your questione.....
Answer:
1.
[tex] {h}^{2} = {p }^{2} + {b}^{2} [/tex]
[tex] {13}^{2} \: = {12}^{2} + {b}^{2} [/tex]
[tex] {b}^{2} = {13}^{2} - {12}^{2} [/tex]
[tex] {b }^{2} = 169 - 144[/tex]
[tex] {b}^{2} = 25/tex]
[tex]b = \sqrt{25} [/tex]
[tex]b = 5[/tex]
hope this helps you all of your question's is base on the formula given above
mark me as brainliest pls