Answer:
-1.833 ; we do not reject the Null.
Pvalue = 0.0409 ; We do not reject the Null
There is no significant evidence to conclude that the number of ounces contained in the cereal boxes is less than 13
Step-by-step explanation:
H0 : ╬╝ = 13
HA : ╬╝ < 13
Test statistic :
(xbar - ╬╝) ├╖ s/sqrt(n)
(12.8 - 13) ├╖ 0.5/sqrt(21)
-0.2 / 0.1091089
= - 1.833
The critical value at ╬▒ = 0.01 ; df = 21 - 1 = 20 = 2.528
-1.833 > - 2. 528 (left tailed test) ; Hence we do not reject the Null.
Test statistic :
Pvalue from Test statistic at DF = 20 ; ╬▒ = 0.01
Pvalue = 0.0409
Pvalue > ╬▒
0.0409 > 0.01 ; Hence, we do not reject H0.
There is no significant evidence to conclude that the number of ounces contained in the cereal boxes is less than 13
