Answer:
25.00mL
Explanation:
It is the volume of NaOH at equiv pt.
This part is just an explanation do not include in your answer:
We can plug the values we have to the equation MV = MV.
The concentration of NaOH in the titration reaction can be elucidated with the volume of NaOH in the reaction from the graph.
The titration is the neutralization reaction of acid with base, resulting in by the formation of salt and water.
The calculation of molar concentration of NaOH in the titration reaction is carried with the expression of :
[tex]\rm Molarity\;NaOH\;\times\;Volume\;NaOH=Molarity\;acid\;\times\;Volume\;acid[/tex]
The volume and molarity of acid, is known in the question as 50 mL and 0.1 M.
The value for the volume of NaOH is required to calculate the concentration of NaOH in the reaction.
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