Answer:
[tex]m_G=214.02g[/tex]
Explanation:
Hello there!
In this case, since the mole fraction of glucose is calculated by dividing the moles of glucose by the addition of the moles of glucose and water, we first need to calculate the moles water and then solve for those of glucose in the mole fraction:
[tex]n_w=\frac{150.0g}{18.02g/mol}=8.32mol\\\\x_G=\frac{n_G}{n_G+n_w} \\\\n_G=\frac{x_Gn_W}{1-x_G} \\\\n_G=\frac{0.125*8.324}{1-0.125} \\\\n_G=1.189mol[/tex]
And finally, we multiply by the molar mass of glucose to obtain:
[tex]m_G=1.189mol*180g/mol\\\\m_G=214.02g[/tex]
Regards!
