Question: A tire on a car has an air pressure of 32 PSI when it is 62 ° F. Overnight the temperature drops to 40° F. What happens to the pressure in the tire overnight
Answer:
30.65 psi
Explanation:
Applying,
P/T = P'/T'..................... Equation 1
Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T'= Final Temperature.
make P' the subject of the equation
P' = PT'/T................. Equation 2
From the question,
Given: P = 32 psi, T = 62 ° F = 289.817 K, T' = 40 ° F = 277.594 K
Substitute these values into equation 2
P' = (32×277.594)/(289.817)
P' = 30.65 psi
Hence the new pressure in the tire is 30.65 psi
