Answer:
F = 1.62 x 10¹⁴ N
Explanation:
The electrostatic force of attraction between the balls can be given by the following formula:
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
where,
F = attractive force = ?
k = Colomb's Constant = 9 x 10⁹ N.m²/C²
q₁ = Charge on ball A = 12 C
q₂ = Charge on ball B = 15 C
r = distanc between the balls = 10 cm = 0.1 m
Therefore,
[tex]F = \frac{(9\ x\ 10^9\ Nm^2/C^2)(12\ C)(15\ C)}{(0.1\ m)^2}[/tex]
F = 1.62 x 10¹⁴ N
