Answer:
Step-by-step explanation:
Here, we want to write as a single logarithm
Recall;
Log a + Log b = Log ab
Log a - Log b = Log (a/b)
so starting with the bracket, we have;
Log 2 + Log X - Log 3y
Furthermore, we have;
Log 2x - Log 3y
Finally, we have;
Log (2x/3y)
