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Answer :

Step-by-step explanation:

[tex]2 {x}^{2} - 6x + 3 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{6± \sqrt{12} }{4} \\ x = 2.4 \: or \: 0.6[/tex]

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