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Elise6718go
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A 7.0 kilogram ball traveling east 5.0 meters per second collided head on with a 3.0- kilogram ball traveling west at 6.0 meters per second. After the collision, the 7.0 kilogram ball bounces off the other and travels west at 2 m/s. Determine the final velocity of the 3.0 kilogram ball.

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Answer :

Trancescientgo

Answer:

10.3 m/s to the east

Explanation:

Use the law of conservation of linear momentum:

m1Vi1 + m2Vi2 = m1Vf1 + m2Vf2

We know that

m1 = 7 kg. Vi1 = +5.0 m/s (east is +) Vf1 = -2.0 m/s

m2 = 3.0 kg. Vi2 = -6.0 m/s (west is -) Vf2 = ?

or

(7)(5) + (3)(-6) = (7)(-2) + 3Vf2

Solving for Vf2, we get

Vf2 = 10.3 m/s (to the east)

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