Given :
Two similar triangle.
To Find :
The ratio of the area of triangle abc to the area of triangle edc.
Solution :
ΔABC ~ ΔAPQ (AA criterion for similar triangles)
Since both the triangles are similar, using the theorem for areas of similar triangles we have :
[tex]\dfrac{Area \ of \ \Delta ABC}{Area \ of \ \Delta EDC} = \dfrac{AC}{EC}\\\\\dfrac{Area \ of \ \Delta ABC}{Area \ of \ \Delta EDC} = \dfrac{20+8}{20}\\\\\dfrac{Area \ of \ \Delta ABC}{Area \ of \ \Delta EDC} = 1.4[/tex]
Therefore, ratio of area of triangle is 1.4 .
