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To find the average rate (speed) of a car traveling on a highway, the distance traveler is divided by the time: R=D/T. If the distance is D=36/x^2-36 miles and the time is T=6x^2+6x/x^2+7x+6 hours, find a simplified expression for the average rate of the car.
a) 1/x
b) 6/x-6
c) 6/x^2-6x
d) 1/x^2-6x

Answer :

Answer:

It's C

Step-by-step explanation:

Just took the quiz and got it right.

The average rate (speed) of a car traveling on a highway, the distance traveler is divided by the time: R=D/T would be c) 6/x^2-6x.

How to find the average rate of change of something?

Let the thing that is changing be y and the thing with which the rate is being compared is x,

then we have the average rate of change of y as x changes as:

[tex]\text{Average rate} = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]

where when

[tex]x = x_1, y = y_1\\and \\x = x_2, y = y_2[/tex]

The distance traveler is divided by the time: R=D/T.

If the distance is  [tex]D=\dfrac{36}{x^2}-36[/tex]miles

the time is  [tex]T=6x^2+\dfrac{6x}{x^2}+7x+6\: hours,[/tex]

The average speed of a car traveling = Distance / Time

= [tex]\dfrac{\dfrac{36}{x^2}-36}{6x^2+\dfrac{6x}{x^2}+7x+6}[/tex]

= [tex]\dfrac{{36}-36{x^2}}{6x^4+{6x}+7{x^3}+6{x^2}}[/tex]

= [tex]\dfrac{6}{x^2}-6x[/tex]

Learn more about speed;

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