Answer:
[tex]A). ~(10)sin(40^o)=AC[/tex]
Step-by-step explanation:
∠B, opposite = AC
Hypotenuse = AB
So...
→ [tex]Sin(B)=AC/AB[/tex]
→ [tex]Sin (40^o)=AC/10[/tex]
→ [tex]AC=(10)Sin(40^o)[/tex]
→[tex](10)sin(40^o)=AC[/tex]
[tex]--------[/tex]
[tex]hope ~ it ~helps\\\\have ~ a ~ great ~ day!![/tex]
