Answer: G
This problem requires you to utilize the equation for the volume of a sphere. The volume of a sphere is [tex]\frac{4}{3}\pi r^{2}[/tex]. Because we are given the radius, the equation should be [tex]\frac{4}{3}\pi 12^{2}[/tex]. Simplify the equation to get 7238.23 [tex]cm^{3}[/tex]. (The mass doesn't really matter in this scenario. It's just additional information.)
