Answer :
Explanation:
[tex]kinetic \: energy = \frac{1}{2} m {v}^{2} \\ but \: {v}^{2} = {u}^{2} + 2gh \\ {v}^{2} = 0 + (2 \times 10 \times 2) \\ v = 6.32 \: m {s}^{ - 1} \\ k.e = \frac{1}{2} \times 2.5 \times 6.32 {}^{2} \\ = 50 \: joules[/tex]
[tex]potential \: energy = mgh \\ = 2.5 \times 2 \times 10 \\ = 50 \: joules[/tex]