Answer:
The cost is #15.90
Step-by-step explanation:
See comment for complete question
Given
[tex]P \to Potato[/tex]
[tex]C \to Carrot[/tex]
[tex]3P + 2C = 5.08[/tex]
[tex]P = 1.24[/tex]
Required
[tex]12P + 1\frac{1}{2}C = ??[/tex]
First, we solve for C
Substitute [tex]P = 1.24[/tex] in [tex]3P + 2C = 5.08[/tex]
[tex]3 * 1.24 + 2C = 5.08[/tex]
[tex]3.72 + 2C = 5.08[/tex]
Collect like terms
[tex]2C = 5.08 - 3.72[/tex]
[tex]2C = 1.36[/tex]
Solve for C
[tex]C = \frac{1.36}{2}[/tex]
[tex]C = 0.68[/tex]
So, we have:
[tex]P = 1.24[/tex]
[tex]C = 0.68[/tex]
[tex]12P + 1\frac{1}{2}C = ??[/tex] becomes
[tex]12P + 1\frac{1}{2}C = 12*1.24 + 1\frac{1}{2}*0.68[/tex]
[tex]12P + 1\frac{1}{2}C = 14.88 + 1.02[/tex]
[tex]12P + 1\frac{1}{2}C = 15.90[/tex]
