9514 1404 393
Answer:
[tex]\displaystyle S_n=\sum_{k=1}^n{\frac{3^k}{3k-2}}[/tex]
Step-by-step explanation:
The sequence terms appear to have numerators that are powers of 3, and denominators that are a linear (arithmetic) sequence with a first term of 1 and a common difference of 3.
numerator: 3^x
denominator: 1 +3(n -1) = 3n-2
Then the sum of n terms of the sequence can be described by ...
[tex]\displaystyle \boxed{S_n=\sum_{k=1}^n{\frac{3^k}{3k-2}}}[/tex]
