Answer:
Explanation:
I'm assuming your charge is in Coulombs so I will proceed that way. The formula for this electric field problem is
[tex]E=\frac{kQ}{r^2}[/tex] where k = 9.0 × 10⁹. Filling in:
[tex]E=\frac{(9.0*10^9)(1.25*10^{-3})}{.4^2}[/tex] gives us an electric field value of
7.0 × 10⁷ N/C
