Graph a line that contains the point (-6,1) and has a slope of 5

Answer:
Step-by-step explanation:
Equation of a line passing through a point (h, k) and slope 'm' is given by,
y - h = m(x - k)
Equation of a line passing through (-6, 1) and slope = 5,
y - 1 = 5(x + 6)
y = 5x + 31
Input-output values of the given equation,
x -6 -4 -2 0
y 1 11 21 31
Now plot these points on a graph.