Answer:
[tex]9^{2x-1} = 2\\[/tex]
Step-by-step explanation:
According to the law of logarithm;
[tex]If \ log_ab = x\\a^x = b[/tex]
Given
[tex]\log_9\left(2\right)=2x-1[/tex]
Comparing with the original expression;
a = 9, b = 2 and c = 2x - 1
Substitute into the result indicinal expression;
[tex]9^{2x-1} = 2\\[/tex]
This gives the required exponential equation
