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Answer :

Answer:

[tex]5[/tex]

Step-by-step explanation:

[tex](2−i)(2+i)[/tex]

[tex]2(2+i)−i(2+i)\\ 2⋅2+2i−i(2+i) \\2⋅2+2i−i⋅2−ii[/tex]

[tex]4+2i−2i \\ 5+2i−2i \\ 5+0 \\ 5[/tex]

Hope it is helpful...