Answer :
9514 1404 393
Answer:
63°
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
tan(G) = HF/HG
G = arctan(HF/HG) = arctan(2.9/1.5) ≈ 63°

9514 1404 393
Answer:
63°
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
tan(G) = HF/HG
G = arctan(HF/HG) = arctan(2.9/1.5) ≈ 63°