Answer :
He has twenty nine $10 coins and twenty $20 coins
Let x be number of $10 coins and y be number of $20 coins
x + y = 49. Number of coins
10x + 20y = 690. Value of coins
Multiply the first equation by 10
10x + 10y = 490
Subtract from the second equation
10y = 200
y = 20
Substitute into equation 1
x + 20 = 49
x = 29
Let x be number of $10 coins and y be number of $20 coins
x + y = 49. Number of coins
10x + 20y = 690. Value of coins
Multiply the first equation by 10
10x + 10y = 490
Subtract from the second equation
10y = 200
y = 20
Substitute into equation 1
x + 20 = 49
x = 29