Answer:
35 m
Explanation:
Given :
The distance of the path from the ground to the tree limb = 50 m
The angle between the path of flight of the bird towards the tree limb and the ground = 45 degrees
Therefore we can determine the height above which the bird perched above the ground by using the rules of the trigonometric ratios as;
We know that ,
[tex]$\sin 45^\circ =\frac{\text{perpendicular}}{\text{hypothenus}}$[/tex]
[tex]$\sin 45^\circ =\frac{\text{BC}}{\text{AC}}$[/tex]
[tex]$0.7 =\frac{\text{BC}}{\text{50}}$[/tex]
[tex]\text{BC }= 0.7 \times 50[/tex]
= 35
Therefore, the bird perched on the tree limb at a height of 35 m.
