x = -1
Step-by-step explanation:
[tex] {4}^{5x} = {2}^{2(5x)} = {2}^{10x} [/tex]
[tex] {( \frac{1}{32}) }^{(1 - x)} = {2}^{ - 5(1 - x)} = {2}^{(5x - 5)} [/tex]
or
[tex] {2}^{10x} = {2}^{(5x - 5)} [/tex]
Since both sides have the same base, we can write
10x = 5x - 5
or
5x = -5
x = -1