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Answer :

Answer:

L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

Step-by-step explanation:

f ( t ) = 10 cos ( 12t + 60°) u(t)

attached below is a detailed solution of the given problem

L(f(t)) = [tex]\frac{5s - 60\sqrt{3} }{s^2 + 144}[/tex]

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