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A survey of 2392 adults ages 18 and over asked what type of food they would be most likely to choose at a restaurant. The results are shown in the figure.

A circle graph titled Survey Results is divided into 6 regions showing different types of restaurants. Starting from the top right, the regions are labeled, American 670, Italian 526, Mexican 407, Chinese 383, Japanese 167, Other 239.

What is the probability that an adult chosen at random prefers Italian food? Round your answer to the nearest whole percent.

Answer :

Answer:

22%

Step-by-step explanation:

their is a total of 2392 adults, the number of people, who would be most likely to chose Italian food is 526.

p= 526/ 2392=22%

The probability of choosing Italian food is 21.9%.

What is probability?

"Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one".

For the given situation,

Total number of adults = 2392

American food = 670

Italian food = 526

Mexican food = 407

Chinese food = 383

Japanese food = 167

Others = 239

The event is the probability of choosing Italian food.

[tex]P(e)=\frac{526}{2392}[/tex]

ā‡’[tex]P(e)=0.219[/tex]

Rounded to nearest whole percent = [tex]0.219[/tex] Ɨ [tex]100[/tex]

ā‡’[tex]21.9\%[/tex]

Hence we can conclude that the probability of choosing Italian food is 21.9%.

Learn more about probability here

brainly.com/question/13604758

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