Answer :
Answer:
C
Step-by-step explanation:
Using the rules of logarithms
loga + logb = log(ab)
loga - logb = log([tex]\frac{a}{b}[/tex] )
log[tex]x^{n}[/tex] ⇔ nlogx
Given
4lnx + ln3 - lnx
= 3lnx + ln3
= lnx³ + ln3
= ln(x³ × 3)
= ln(3x³) → C
Answer:
C
Step-by-step explanation:
Using the rules of logarithms
loga + logb = log(ab)
loga - logb = log([tex]\frac{a}{b}[/tex] )
log[tex]x^{n}[/tex] ⇔ nlogx
Given
4lnx + ln3 - lnx
= 3lnx + ln3
= lnx³ + ln3
= ln(x³ × 3)
= ln(3x³) → C