Answer:
Fewer students are between 44 and 52 inches than between 52 and 60 inches in height.
Step-by-step explanation:
Given
See attachment for histogram
Required
Select the true statement
Option A: Class 46-50 = 12 students
From the histogram, we have:'
[tex]Class\ 46 - 48 = 8; Class\ 48 - 50 = 3[/tex]
So:
[tex]Class\ 46 - 48 = Class\ 46 - 48 + Class\ 48 - 50[/tex]
[tex]Class\ 46 - 48 = 8+ 3[/tex]
[tex]Class\ 46 - 48 = 11[/tex]
(a) is false
Option B: %Class 52-54 = 18%
From the histogram, we have:'
[tex]Class\ 52-54 = 18[/tex]
and
[tex]Total = 53[/tex]
So, the percentage is:
[tex]\% Class\ 52-54 = \frac{Class\ 52-54}{Total}[/tex]
[tex]\% Class\ 52-54 = \frac{18}{53}[/tex]
[tex]\% Class\ 52-54 = 0.3396[/tex]
Express as percentage:
[tex]\% Class\ 52-54 = 33.96\%[/tex]
(b) is false
Option C: Class 54-60 > Class 46 - 50 students
From the histogram, we have:'
[tex]Class\ 54-60 =Class\ 54-56 + Class\ 56-58 + Class\ 58-60[/tex]
[tex]Class\ 54-60 = 4 + 4+3[/tex]
[tex]Class\ 54-60 = 11[/tex]
In (a), we have:
[tex]Class\ 46 - 48 = 11[/tex]
By comparison:
[tex]Class\ 54-60 =Class\ 46 - 48 = 11[/tex]
(c) is false
Option D: Class 44-52 < Class 52 - 60 students
From the histogram, we have:'
[tex]Class\ 44-52 =Class\ 44-56 + Class\ 46-48 + Class\ 48-50 +Class\ 50-52[/tex]
[tex]Class\ 44-52 = 4+8+3+9[/tex]
[tex]Class\ 44-52 = 24[/tex]
[tex]Class\ 52-60 =Class\ 52 - 54 + Class\ 54-56 + Class\ 56-58 + Class\ 58-60[/tex]
[tex]Class\ 52-60 = 18+ 4 + 4+3[/tex]
[tex]Class\ 52-60 = 29[/tex]
By comparison:
[tex]24 < 29[/tex]
i.e.
[tex]Class\ 44 - 55 < Class\ 52 - 60[/tex]
(d) is true
