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A baseball of mass 0.145 kg is thrown at a speed of 40.0 m/s. The batter strikes the ball with a force of 15,000 N; the bat and ball are in contact for 0.500 ms. The force is exactly opposite to the original direction of the ball. Determine the final speed of the ball.

Answer :

Lanuelgo

The final speed of the ball is 91.72 m/s.

Given the following data:

  • Mass of baseball = 0.145 kg
  • Initial speed = 40.0 m/s
  • Force = 15,000 Newton
  • Time = 0.500 milliseconds (ms) to seconds = 0.0005 seconds.

To find the final speed of the ball, we would use the following formula:

[tex]F = \frac{M(V - U)}{t}[/tex]

Where:

  • F is the force applied.
  • u is the initial speed.
  • v is the final speed.
  • t is the time measured in seconds.

Substituting the parameters into the formula, we have;

[tex]15000 = \frac{0.145(V \;- \;40)}{0.0005}\\\\15000(0.0005) = 0.145(V \;- \;40)\\\\7.5 = 0.145V - 5.8\\\\0.145V = 7.5 + 5.8\\\\0.145V = 13.3\\\\V = \frac{13.3}{0.145}[/tex]

Final speed, V = 91.72 m/s

Therefore, the final speed of the ball is 91.72 m/s.

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