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Answer :

Caylusgo

Hello,

Let's x² the square number

and 3*y the multiple of 3.

[tex]x^2+3y=90\\\\\boxed{y=-\dfrac{1}{3} x^2+30}\\\\[/tex]

2 solutions : for (x,y) as integers : (-6,18) and (6,18)

but one solution for (x²,3y) as integers : (36,54)

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