1. Can cross multiplication be used to solve this problem? Why or why not?
HELP

Answer:
Step-by-step explanation:
Cross multiplication can be used but not in the beginning. First x should be isolated.
[tex]3 +\frac{5}{x}=\frac{7}{x}\\\\[/tex]
Now subtract [tex]\frac{5}{x}[/tex] from both sides
[tex]3 = \frac{7}{x}-\frac{5}{x}\\\\3=\frac{7-5}{x}\\\\3=\frac{2}{x}[/tex]
In this stage, cross multiplication can be used.
[tex]\frac{3}{1}=\frac{2}{x}\\\\3*x=2*1\\\\x = \frac{2}{3}[/tex]
Answer:
x =0 and x =2/3
Step-by-step explanation:
as is no
but if you put an x under the 3 to make 3x/x
then you'd have 3x+5/x = 7/x
to make
3x^2 + 5x = 7x
this makes
3x^2 -2x =0
using the quadratic formula
answers
x =0 and x =2/3