Answer :
Answer:
9.0 L/min
Explanation:
From the given information, the flow rate in the wider section appears to four times that of the narrow section.
Since the flow rate for a pipe at any time (t) = Area (A) × speed (V)
we can say that:
[tex]A_wV_w = A_nV_n[/tex]
Then, the flow rate in the wider section will also be 9.0 L/min. This is because the mass flow rate must be kept constant regardless of the changes in the size of the cross-sectional area.