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The weight gain of beef steers were measured over a 140 day test period. the average daily gains (lb/day) of 10 steers on the same diet were as follows. The tenth steer had a weight gain of 4.02 lb/day.
3.89 3.51 3.97 3.31 3.21 3.36 3.67 3.24 3.27
determine the mean and median.

Answer :

MrRoyalgo

Answer:

[tex]\bar x = 3.545[/tex]

[tex]Median = 3.435[/tex]

Step-by-step explanation:

Given

[tex]x:3.89, 3.51, 3.97, 3.31, 3.21, 3.36, 3.67, 3.24, 3.27[/tex]

[tex]10th: 4.02[/tex]

Solving (a): The mean

This is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{3.89 +3.51 +3.97 +3.31 +3.21 +3.36 +3.67 +3.24 +3.27+4.02}{10}[/tex]

[tex]\bar x = \frac{35.45}{10}[/tex]

[tex]\bar x = 3.545[/tex]

Solving (b): The median

First, we sort the data; as follows:

[tex]3.21, 3.24, 3.27, 3.31, 3.36, 3.51, 3.67, 3.89, 3.97, 4.02[/tex]

[tex]n = 10[/tex]

So, the median position is:

[tex]Median = \frac{n + 1}{2}th[/tex]

[tex]Median = \frac{10 + 1}{2}th[/tex]

[tex]Median = \frac{11}{2}th[/tex]

[tex]Median = 5.5th[/tex]

This means that the median is the average of the 5th and 6th item

[tex]Median = \frac{3.36 + 3.51}{2}[/tex]

[tex]Median = \frac{6.87}{2}[/tex]

[tex]Median = 3.435[/tex]

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