Answer :
Answer:
The test statistics will be "-0.876",
Step-by-step explanation:
Given:
- [tex]\bar x=18.6[/tex]
- [tex]\mu = 19[/tex]
- [tex]s = 3.1[/tex]
- [tex]n = 46[/tex]
According to the question,
Level of significance will be:
= 0.05
Now,
The test statistics will be:
= [tex]\frac{\bar x-\mu}{\frac{s}{\sqrt{n} } }[/tex]
By substituting the values, we get
= [tex]\frac{18.6-19}{\frac{3.1}{\sqrt{46} } }[/tex]
= [tex]-\frac{2.713}{3.1}[/tex]
= [tex]-0.876[/tex]