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Answer :

Msm555go

Answer:

Solution given:

relationship between perpendicular and hypotenuse is given by sin angle

Sin 45=opposite/hypotenuse

[tex]\frac{\sqrt{2}}{2}=\frac{x}{\sqrt{5}}[/tex]

z=[tex]\frac{\sqrt{2}}{2}*\sqrt{5}[/tex]

x=[tex]\frac{\sqrt{10}}{2}[/tex]

The value of x is;[tex]\frac{\sqrt{10}}{2}[/tex]

CoastsideDadgo

Answer:

[tex]\frac{\sqrt{10} }{2}[/tex]

Step-by-step explanation:

on a 45 - 45 - 90 triangle if the sides are x then the hypotenuse is x[tex]\sqrt{2}[/tex]

so,

[tex]\sqrt{5}[/tex] = x[tex]\sqrt{2}[/tex]                  (Divide by [tex]\sqrt{2}[/tex] )

[tex]\frac{\sqrt{5} }{\sqrt{2} }[/tex] = x                        (rationalize the denominator)

[tex]\frac{\sqrt{5} }{\sqrt{2} }[/tex] · [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{10} }{\sqrt{4} }[/tex] = [tex]\frac{\sqrt{10} }{2}[/tex]

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