HELP ME PLEASE ASAP!!!
Find the length of the arc.
A.125pi/6mi
B.5400pimi
C.15pi
D.135pi

Answer:
[tex]15\pi[/tex]
Step-by-step explanation:
[tex] \frac{ \theta}{360} \times 2\pi \: r \\ \frac{150}{360} \times 2 \times \pi \times 18 \\ \frac{5400\pi}{360} \\ = 15\pi[/tex]