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Answer :

using Pythagorean triplet

[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]

[tex]\\ \sf\longmapsto x^2=19.6^2-15.4^2[/tex]

[tex]\\ \sf\longmapsto x^2=384.16-237.16[/tex]

[tex]\\ \sf\longmapsto x^2=147[/tex]

[tex]\\ \sf\longmapsto x=\sqrt{147}[/tex]

[tex]\\ \sf\longmapsto x=12.1[/tex]

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