Answer:
Step-by-step explanation:
1)
[tex]Sin \ \alpha = \frac{oppsoite \ side \ of \alpha }{hypotenuse}=\frac{QR}{PR}\\\\\\Cos \ \alpha = \frac{adjacent \ side \ of \alpha }{hypotenuse}=\frac{PQ}{PR}\\\\\\tan \ \alpha = \frac{oppsoite \ side \ of \alpha }{adjacent \ side \ of \alpha}=\frac{QR}{PQ}\\\\[/tex]
[tex]Sin \ \beta =\frac{opposite \ of\ \beta }{hypotenuse}=\frac{PQ}{PR}\\\\\\Cos \ \beta =\frac{adjacent \ of\ \beta }{hypotenuse}=\frac{QR}{PR}\\\\\\tan \ \beta =\frac{opposite \ of\ \beta }{adjacent \ of\ \beta }=\frac{PQ}{QR}\\\\[/tex]
